Question from IT foundation. A, B, and C can do a work in 20, 45, and 120 days,respectively. They started the work. A left 10 daysbefore and B left 5 days before the completion ofwork. In how many days is the total work completed?

If N is the total time taken, it means that
A worked for (N -10) days, B for (N - 5) days
and C for N days.
Hence (N - 10) * 1/20 + ( N - 5)*1/45 +
N/120 = 1

(N - 10) * 18 + ( N -5)* 8 + 3 N = 360
18 N - 180 + 8N - 40 + 3 N = 360
29N = 580

N = 20

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