Top 5 questions related to Ratio for class 8.
1.If the ratio of chocolates to ice-cream cones in a box is 5:8 and the number of chocolates is 30, find the number of ice-cream cones.
Solution:
Let the number of chocolates be 5x and the number of ice-cream cones be 8x.
5x = 30
→ x = 6.
Therefore, number of ice-cream cones in the box = 8*6 = 48.
2.Two numbers are in the ratio 3 : 4. If the sum of numbers is 63, find the numbers.
Solution:
Sum of the terms of the ratio = 3 + 4 = 7
Sum of numbers = 63
Therefore, first number = 3/7 × 63 = 27
Second number = 4/7 × 63 = 36
Therefore, the two numbers are 27 and 36.
3. If x : y = 1 : 2, find the value of (2x + 3y) : (x + 4y)
Solution:
x : y = 1 : 2 means x/y = 1/2
Now, (2x + 3y) : (x + 4y) = (2x + 3y)/(x + 4y) [Divide numerator and denominator by y.]
= [(2x + 3y)/y]/[(x + 4y)/2] = [2(x/y) + 3]/[(x/y) + 4], put x/y = 1/2
We get = [2 (1/2) + 3)/(1/2 + 4) = (1 + 3)/[(1 + 8)/2] = 4/(9/2) = 4/1 × 2/9 = 8/9
Therefore the value of (2x + 3y) : (x + 4y) = 8 :9.
4. A bag contains $510 in the form of 50 p, 25 p and 20 p coins in the ratio 2 : 3 : 4. Find the number of coins of each type.
Solution:
Let the number of 50 p, 25 p and 20 p coins be 2x, 3x and 4x.
Then 2x × 50/100 + 3x × 25/100 + 4x × 20/100 = 510
x/1 + 3x/4 + 4x/5 = 510
(20x + 15x + 16x)/20 = 510
⇒ 51x/20 = 510
x = (510 × 20)/51
x = 200
2x = 2 × 200 = 400
3x = 3 × 200 = 600
4x = 4 × 200 = 800.
Therefore, number of 50 p coins, 25 p coins and 20 p coins are 400, 600, 800 respectively.
5.Set up all possible proportions from the numbers 8, 12, 20, 30.
Solution:
We note that 8 × 30 = 240 and 12 × 20 = 240
Thus, 8 × 30 = 12 × 20 ………..(I)
Hence, 8 : 12 = 20 : 30 ……….. (i)
We also note that, 8 × 30 = 20 × 12
Hence, 8 : 20 = 12 : 30 ……….. (ii)
(I) can also be written as 12 × 20 = 8 × 30
Hence, 12 : 8 = 30 : 20 ……….. (iii)
Last (I) can also be written as
12 : 30 = 8 : 20 ……….. (iv)
Thus, the required proportions are 8 : 12 = 20 : 30
8 : 20 = 12 : 30 12 : 8 = 30 : 20 12 : 30 = 8 : 20
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